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Problem Correct order of bond angle in given species is :
a. SiO 4 4 − > PCl 3 > NCl 3 > SbH 3 > H 2 Te \text{SiO}_4^{4-} > \text{PCl}_3 > \text{NCl}_3 > \text{SbH}_3 > \text{H}_2\text{Te} SiO 4 4 − > PCl 3 > NCl 3 > SbH 3 > H 2 Te SiO 4 4 − > NCl 3 > PCl 3 > SbH 3 > H 2 Te \text{SiO}_4^{4-} > \text{NCl}_3 > \text{PCl}_3 > \text{SbH}_3 > \text{H}_2\text{Te} SiO 4 4 − > NCl 3 > PCl 3 > SbH 3 > H 2 Te SiO 4 4 − > H 2 Te > SbH 3 > PCl 3 > NCl 3 \text{SiO}_4^{4-} > \text{H}_2\text{Te} > \text{SbH}_3 > \text{PCl}_3 > \text{NCl}_3 SiO 4 4 − > H 2 Te > SbH 3 > PCl 3 > NCl 3 NCl 3 > PCl 3 > SiO 4 4 − > SbH 3 > H 2 Te \text{NCl}_3 > \text{PCl}_3 > \text{SiO}_4^{4-} > \text{SbH}_3 > \text{H}_2\text{Te} NCl 3 > PCl 3 > SiO 4 4 − > SbH 3 > H 2 Te Browse the problem library