Physics

Problem

r = 5 \times 10^{-4} \text{ m}

\rho = 10^3 \text{ kg m}^{-3}

g = 10 \text{ ms}^{-2}

T = 0.11 \text{ Nm}^{-1}

, the radius of the drop when it detaches from the dropper is approximately a.

1.4 \times 10^{-3} \text{ m}

3.3 \times 10^{-3} \text{ m}

2.0 \times 10^{-3} \text{ m}

4.1 \times 10^{-3} \text{ m}