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Mathematics
Mathematics
Problem
Show that
cot
(
π
4
+
x
)
⋅
cot
(
π
4
−
x
)
=
1
\cot \left( \frac{\pi}{4} + x \right) \cdot \cot \left( \frac{\pi}{4} - x \right) = 1
cot
(
4
π
+
x
)
⋅
cot
(
4
π
−
x
)
=
1
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