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Mathematics
Mathematics
Problem
Prove that
sin
600
∘
tan
(
−
690
∘
)
+
sec
840
∘
cot
(
−
945
∘
)
=
3
/
2
\sin 600^\circ \tan(-690^\circ) + \sec 840^\circ \cot(-945^\circ) = 3/2
sin
60
0
∘
tan
(
−
69
0
∘
)
+
sec
84
0
∘
cot
(
−
94
5
∘
)
=
3/2
.
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