Mathematics

Mathematics

Problem

The function h(x)={39−x2,−3≤x≤0,x2−2x+1,0<x<3h(x)=\begin{cases}3\sqrt{9-x^{2}},&-3\le x\le 0,\\x^{2}-2x+1,&0<x<3\end{cases} is defined on [−3,3][-3,3]. Determine the absolute maximum value of hh on [−3,3][-3,3].

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