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Mathematics
Mathematics
Problem
In any triangle ABC, prove that
a
sin
(
B
−
C
)
+
b
sin
(
C
−
A
)
+
c
sin
(
A
−
B
)
=
0.
a \sin (B - C) + b \sin (C - A) + c \sin (A - B) = 0.
a
sin
(
B
−
C
)
+
b
sin
(
C
−
A
)
+
c
sin
(
A
−
B
)
=
0.
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