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Mathematics
Mathematics
Problem
If
f
(
x
)
=
1
+
cos
2
(
x
2
)
f(x) = \sqrt{1 + \cos^2(x^2)}
f
(
x
)
=
1
+
cos
2
(
x
2
)
, then
f
′
(
π
2
)
f' \left(\frac{\sqrt{\pi}}{2}\right)
f
′
(
2
π
)
is (a)
π
/
6
\sqrt{\pi}/6
π
/6
(b)
−
(
π
/
6
)
-\sqrt{(\pi/6)}
−
(
π
/6
)
(c)
1
/
6
1/\sqrt{6}
1/
6
(d)
π
/
6
\pi/\sqrt{6}
π
/
6
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