Introduction to Quantum Mechanics · Problem 4.69

Quantum Mechanics in Three Dimensions — David J. Griffiths

Physics — Quantum Mechanics · hydrogen_numerical

Problem

Find a few of the Bohr energies for hydrogen by "wagging the dog" (Problem 2.55), starting with Equation 4.53—or, better yet, Equation 4.56; in fact, why not use Equation 4.68 to set ρ0=2n\rho_0 = 2n, and tweak nn? We know that the correct solutions occur when nn is a positive integer, so you might start with n=0.9,1.9,2.9n = 0.9, 1.9, 2.9, etc., and increase it in small increments—the tail should wag when you pass 1, 2, 3, .... Find the lowest three nns, to four significant digits, first for ℓ=0\ell = 0, and then for ℓ=1\ell = 1 and ℓ=2\ell = 2. Warning: Mathematica doesn't like to divide by zero, so you might change ρ\rho to (ρ+0.000001)(\rho + 0.000001) in the denominator. Note: u(0)=0u(0) = 0 in all cases, but u′(0)=0u'(0) = 0 only for ℓ≥1\ell \geq 1 (Equation 4.59). So for ℓ=0\ell = 0 you can use u(0)=0u(0) = 0, u′(0)=1u'(0) = 1. For ℓ>0\ell > 0 you might be tempted to use u(0)=0u(0) = 0 and u′(0)=0u'(0) = 0, but Mathematica is lazy, and will go for the trivial solution u(ρ)≡0u(\rho) \equiv 0; better, therefore, to use (say) u(1)=1u(1) = 1 and u′(0)=0u'(0) = 0.

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