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Mathematics
Problem
A ball is projected vertically so that its height above the ground after
t
t
t
seconds is
s
(
t
)
=
5
t
2
+
2
t
+
1
s(t)=5t^{2}+2t+1
s
(
t
)
=
5
t
2
+
2
t
+
1
metres. Determine the ball’s average vertical velocity between
t
=
2
s
t=2\,\text{s}
t
=
2
s
and
t
=
5
s
t=5\,\text{s}
t
=
5
s
.
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