JEE Advanced 2023 Paper 2 Mathematics Q3

Mathematics

Problem

For any y ∈ ℝ, let cot⁻¹(y) ∈ (0, π) and tan⁻¹(y) ∈ (−π/2, π/2). Then the sum of all the solutions of the equation tan⁻¹(6y/(9 − y²)) + cot⁻¹((9 − y²)/(6y)) = 2π/3 for 0 < |y| < 3, is equal to

Browse the problem library