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Mathematics
Mathematics
Problem
Let
g
(
x
)
=
x
2
tan
x
+
5
x
sec
x
−
7
g(x)=x^{2}\tan x+5x\sec x-7
g
(
x
)
=
x
2
tan
x
+
5
x
sec
x
−
7
. (i) Differentiate
g
(
x
)
g(x)
g
(
x
)
to obtain
g
′
(
x
)
g'(x)
g
′
(
x
)
. (ii) Verify that
g
′
(
0
)
=
5
g'(0)=5
g
′
(
0
)
=
5
. (iii) Hence, write the equation of the tangent to the curve
y
=
g
(
x
)
y=g(x)
y
=
g
(
x
)
at the point where
x
=
0
x=0
x
=
0
.
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