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Problem
Problem
Passage - 3 (Question. 66 to 67) Let
f
(
x
)
=
{
∣
x
∣
,
−
3
≤
x
≤
7
2
x
−
7
,
7
<
x
≤
10
f(x) = \begin{cases} |x|, & -3 \leq x \leq 7 \\ 2x-7, & 7 < x \leq 10 \end{cases}
f
(
x
)
=
{
∣
x
∣
,
2
x
−
7
,
−
3
≤
x
≤
7
7
<
x
≤
10
and
g
(
x
)
=
2
x
+
1
,
−
3
≤
x
≤
10
g(x) = 2x + 1, -3 \leq x \leq 10
g
(
x
)
=
2
x
+
1
,
−
3
≤
x
≤
10
. If the equation
f
(
∣
x
∣
)
+
g
(
∣
x
∣
)
=
k
f(|x|) + g(|x|) = k
f
(
∣
x
∣
)
+
g
(
∣
x
∣
)
=
k
, has exactly two distinct real solutions, then the value of
k
k
k
cannot be (a) 32 (b) 33 (c) 34 (d) 35
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