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Mathematics
Mathematics
Problem
(
sin
−
1
x
)
2
+
(
sin
−
1
y
)
2
+
2
(
sin
−
1
x
)
(
sin
−
1
y
)
=
π
2
(\sin^{-1} x)^2 + (\sin^{-1} y)^2 + 2(\sin^{-1} x)(\sin^{-1} y) = \pi^2
(
sin
−
1
x
)
2
+
(
sin
−
1
y
)
2
+
2
(
sin
−
1
x
)
(
sin
−
1
y
)
=
π
2
, then
x
2
+
y
2
x^2 + y^2
x
2
+
y
2
is equal to: (a) 1 (b)
3
/
2
3/2
3/2
(c) 2 (d)
1
/
2
1/2
1/2
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