JEE Advanced 2017 Paper 2 Chemistry Q1

Chemistry · Solutions, Mixtures & Activities · Phase Equilibria & the Phase Rule

Problem

Pure water freezes at 273 K273\,\mathrm{K} and 1 bar1\,\mathrm{bar}. The addition of 34.5 g34.5\,\mathrm{g} of ethanol to 500 g500\,\mathrm{g} of water changes the freezing point of the solution. Use the freezing point depression constant of water as 2 K kg mol−12\,\mathrm{K\,kg\,mol^{-1}}. The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T). [molecular weight of ethanol is 46 g mol−146\,\mathrm{g\,mol^{-1}}] Among the following, the option representing change in the freezing point is

Related theory

Browse the problem library