Physics

Physics

Problem

A nucleus XX, initially at rest, undergoes alpha decay according to the equation, 92AX→Z228Y+α{}_{92}^{A}X \to {}_{Z}^{228}Y + \alpha Given that: m(Y)=228.03 um(Y) = 228.03 \text{ u}; m(01n)=1.009 um\left({}_0^1n\right) = 1.009 \text{ u}; m(24He)=4.003 um\left({}_2^4\text{He}\right) = 4.003 \text{ u}; m(11H)=1.008 um\left({}_1^1\text{H}\right) = 1.008 \text{ u}. a. Find the values of AA and ZZ in the above process. b. The alpha particle produced in the above process is found to move in a circular track of radius 0.11 m0.11 \text{ m} in a uniform magnetic field of 3 Tesla3 \text{ Tesla} . Find the energy (In MeV) released during the process and the binding energy of the parent nucleus XX .

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