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Mathematics
Mathematics
Problem
The derivative of
tan
−
1
(
1
+
x
2
−
1
x
)
\tan^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)
tan
−
1
(
x
1
+
x
2
−
1
)
with respect to
tan
−
1
(
2
x
1
−
x
2
1
−
2
x
2
)
\tan^{-1}\left(\frac{2x\sqrt{1-x^2}}{1-2x^2}\right)
tan
−
1
(
1
−
2
x
2
2
x
1
−
x
2
)
at
x
=
0
x=0
x
=
0
is (a)
1
/
8
1/8
1/8
(b)
1
/
4
1/4
1/4
(c)
1
/
2
1/2
1/2
(d) 1
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