partial-differential-equations-by-evans · Problem 13

Nonlinear First-Order PDE

Mathematics — Calculus · heat-equation-boundary-value-formula

Problem

Given g:[0,∞)→Rg : [0,\infty) \to \mathbb{R}, with g(0)=0g(0) = 0, derive the formula u(x,t)=x4π∫0t1(t−s)3/2e−x24(t−s)g(s) dsu(x,t) = \frac{x}{\sqrt{4\pi}} \int_0^t \frac{1}{(t-s)^{3/2}} e^{\frac{-x^2}{4(t-s)}} g(s)\, ds for a solution of the initial/boundary-value problem {ut−uxx=0in R+×(0,∞)u=0on R+×{t=0},u=gon {x=0}×[0,∞).\begin{cases} u_t - u_{xx} = 0 & \text{in } \mathbb{R}_+ \times (0,\infty) \\ u = 0 & \text{on } \mathbb{R}_+ \times \{t=0\}, \\ u = g & \text{on } \{x=0\} \times [0,\infty). \end{cases} (Hint: Let v(x,t):=u(x,t)−g(t)v(x,t) := u(x,t) - g(t) and extend vv to {x<0}\{x < 0\} by odd reflection.)

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