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Chemistry
Chemistry
Problem
Calculate emf of half cells given below: (a)
Pt
∣
H
2
∣
HCl
\text{Pt} \mid \text{H}_2 \mid \text{HCl}
Pt
∣
H
2
∣
HCl
2 atm
a
=
0.02
a = 0.02
a
=
0.02
E
O
P
=
0
V
E_{OP} = 0 \text{ V}
E
O
P
=
0
V
(b)
Fe
∣
FeSO
4
\text{Fe} \mid \text{FeSO}_4
Fe
∣
FeSO
4
a
=
0.1
a = 0.1
a
=
0.1
E
O
P
=
0.44
V
E_{OP} = 0.44 \text{ V}
E
O
P
=
0.44
V
(c)
Pt
∣
Cl
2
∣
HCl
\text{Pt} \mid \text{Cl}_2 \mid \text{HCl}
Pt
∣
Cl
2
∣
HCl
10 atm
a
=
0.1
a = 0.1
a
=
0.1
E
O
P
=
−
1.36
V
E_{OP} = -1.36 \text{ V}
E
O
P
=
−
1.36
V
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