Problem

Problem

Solve cot⁡θ=sin⁡2θ\cot \theta = \sin 2\theta by substituting sin⁡2θ=2tan⁡θ1+tan⁡2θ and again by substituting\sin 2\theta = \frac{2 \tan \theta}{1 + \tan^2 \theta} \text{ and again by substituting} sin⁡2θ=2sin⁡θ⋅cos⁡θ\sin 2\theta = 2 \sin \theta \cdot \cos \theta and check whether the two answer are same or not.

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