Mathematics

Problem

x

is real and

4y^2 + 4xy + x + 6 = 0

, then the complete set of values of

x

for which

y

is real, is: (a)

x \le -2

x \ge 3

(b)

x \le 2

x \ge 3

(c)

x \le -3

x \ge 2

(d)

-3 \le x \le 2