Physics

Physics

Problem

A rocket is launched normal to the surface of the Earth, away from the Sun, along the line joining the Sun and the Earth. The Sun is 3×1053 \times 10^5 times heavier than the Earth and is at a distance 2.5×1042.5 \times 10^4 times larger than the radius of the Earth. The escape velocity from Earth's gravitational field is ve=11.2 km s−1v_e = 11.2 \text{ km s}^{-1} . The minimum initial velocity ( vsv_s ) required for the rocket to be able to leave the Sun-Earth system is closest to (Ignore the rotation and revolution of the Earth and the presence of any other planet) [Adv. 2017] a. vs=22 km s−1v_s = 22 \text{ km s}^{-1} b. vs=42 km s−1v_s = 42 \text{ km s}^{-1} c. vs=62 km s−1v_s = 62 \text{ km s}^{-1} d. vs=72 km s−1v_s = 72 \text{ km s}^{-1}

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