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Physics
Physics
Problem
Clockwise mesh currents
I
1
I_1
I
1
and
I
2
I_2
I
2
are assigned to two adjacent loops that share a resistor
R
R
R
. Taking the positive direction through
R
R
R
to be the same as that of
I
1
I_1
I
1
, the current through
R
R
R
is a)
I
1
+
I
2
I_1+I_2
I
1
+
I
2
b)
I
2
−
I
1
I_2-I_1
I
2
−
I
1
c)
I
1
−
I
2
I_1-I_2
I
1
−
I
2
d)
I
1
I
2
I
1
+
I
2
\dfrac{I_1I_2}{I_1+I_2}
I
1
+
I
2
I
1
I
2
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