If f(x)={x(e4/x−e−4/xe4/x+e−4/x),x≠00,x=0f(x) = \begin{cases} x \left( \frac{e^{4/x} - e^{-4/x}}{e^{4/x} + e^{-4/x}} \right), & x \ne 0 \\ 0, & x = 0 \end{cases}…

Mathematics

Problem

If f(x)={x(e4/x−e−4/xe4/x+e−4/x),x≠00,x=0f(x) = \begin{cases} x \left( \frac{e^{4/x} - e^{-4/x}}{e^{4/x} + e^{-4/x}} \right), & x \ne 0 \\ 0, & x = 0 \end{cases} , then at x=0x = 0 , f(x)f(x) is a. differentiable b. not differentiable c. f′(0)=−1f'(0) = -1 d. f′(0)=1f'(0) = 1

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