The potential energy of a particle of mass 5 kg moving in xy -plane is given as U=(7x+24y) joule, x and y being in metre. Initially at t=0 , the particle is at the origin (0, 0) moving with a velocity of (8.6i^+23.2j^) ms−1 . Then
a. The velocity of the particle at t=4 s , is 5 ms−1
b. The acceleration of the particle is 5 ms−2
c. The direction of motion of the particle initially (at t=0 ) is at right angles to the direction of acceleration
d. The path of the particle is circle