Physics

Physics

Problem

The fission of

^{235}\text{U}

by thermal neutrons can be represented as

^{235}\text{U}+n \rightarrow ^{144}\text{Ba}+^{89}\text{Kr}+3n+Q.

Given the atomic masses:

^{235}\text{U}: 235.0439\,u

, neutron:

1.0087\,u

,

^{144}\text{Ba}: 143.9229\,u

,

^{89}\text{Kr}: 88.9176\,u

, and

1\,u = 931.5\,\text{MeV}/c^{2}

, calculate

Q

(energy released) for one fission event. a)

\approx 189\,\text{MeV}

b)

\approx 215\,\text{MeV}

c)

\approx 173\,\text{MeV}

d)

\approx 92\,\text{MeV}

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