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Physics
Physics
Problem
A proton is released from rest at
x
=
0
x = 0
x
=
0
, where the electric potential is
12
V
12\,\text{V}
12
V
. It moves to
x
=
0.020
m
x = 0.020\,\text{m}
x
=
0.020
m
, where the potential is
5.0
V
5.0\,\text{V}
5.0
V
. Determine the proton’s speed at
x
=
0.020
m
x = 0.020\,\text{m}
x
=
0.020
m
. (Proton mass:
1.67
×
10
−
27
kg
1.67 \times 10^{-27}\,\text{kg}
1.67
×
1
0
−
27
kg
,
e
=
1.60
×
10
−
19
C
e = 1.60 \times 10^{-19}\,\text{C}
e
=
1.60
×
1
0
−
19
C
)
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