Mathematics

Mathematics

Problem

Show that ∣a+b∣2+∣a−b∣2=2(∣a∣2+∣b∣2)|\mathbf{a}+\mathbf{b}|^{2}+|\mathbf{a}-\mathbf{b}|^{2}=2\bigl(|\mathbf{a}|^{2}+|\mathbf{b}|^{2}\bigr) for any vectors a\mathbf{a} and b\mathbf{b}.

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