Classical Dynamics of Particles and Systems · Problem 10-13

Dynamics of Rigid Bodies — Marion & Thornton

Physics — Mechanics · southerly-deflection-falling-particle

Problem

Refer to Example 10.3 concerning the deflection from the plumb line of a particle falling in Earth's gravitational field. Take gg to be defined at ground level and use the zeroth order result for the time-of-fall, T=2h/gT = \sqrt{2h/g}. Perform a calculation in second approximation (i.e., retain terms in ω2\omega^2) and calculate the southerly deflection. There are three components to consider: (a) Coriolis force to second order (C1C_1), (b) variation of centrifugal force with height (C2C_2), and (c) variation of gravitational force with height (C3C_3). Show that each of these components gives a result equal to Cih2gω2sin⁡λcos⁡λC_i \frac{h^2}{g}\omega^2\sin\lambda\cos\lambda with C1=2/3C_1 = 2/3, C2=5/6C_2 = 5/6, and C3=5/2C_3 = 5/2. The total southerly deflection is therefore (4h2ω2sin⁡λcos⁡λ)/g(4h^2\omega^2\sin\lambda\cos\lambda)/g.

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