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Mathematics
Problem
The equation
2
×
5
x
+
2
=
7
2 \times 5^{x+2} = 7
2
×
5
x
+
2
=
7
has the solution: A.
x
=
1
x = 1
x
=
1
B.
x
=
log
5
(
7
2
)
x = \log_5\left(\frac{7}{2}\right)
x
=
lo
g
5
(
2
7
)
C.
x
=
log
5
(
7
2
)
−
2
x = \log_5\left(\frac{7}{2}\right) - 2
x
=
lo
g
5
(
2
7
)
−
2
D.
x
=
log
7
(
5
2
)
−
2
x = \log_7\left(\frac{5}{2}\right) - 2
x
=
lo
g
7
(
2
5
)
−
2
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