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Mathematics
Mathematics
Problem
Solve the differential equation and find its particular solution when
y
=
0
y=0
y
=
0
,
x
=
1
x=1
x
=
1
.
(
1
+
x
2
)
d
y
+
(
2
x
y
)
d
x
=
1
1
+
x
2
d
x
(1+x^2)dy + (2xy)dx = \frac{1}{1+x^2} dx
(
1
+
x
2
)
d
y
+
(
2
x
y
)
d
x
=
1
+
x
2
1
d
x
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