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Mathematics
Mathematics
Problem
Calculate
d
d
x
[
ln
(
1
−
2
x
)
]
\displaystyle \frac{d}{dx}\Big[\ln\big(\sqrt{\,1-2x\,}\big)\Big]
d
x
d
[
ln
(
1
−
2
x
)
]
. a)
−
1
2
(
1
−
2
x
)
-\dfrac{1}{2(1-2x)}
−
2
(
1
−
2
x
)
1
b)
−
1
1
−
2
x
-\dfrac{1}{1-2x}
−
1
−
2
x
1
c)
1
1
−
2
x
\dfrac{1}{1-2x}
1
−
2
x
1
d)
−
1
(
1
−
2
x
)
2
-\dfrac{1}{(1-2x)^{2}}
−
(
1
−
2
x
)
2
1
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