Lebl-Basic-Analysis-I · Problem 3.5.9

Continuous Functions

Mathematics · limits-at-infinity

Problem

Suppose f:R→Rf : \mathbb{R} \to \mathbb{R} is a 2-periodic function, that is f(x+2)=f(x)f(x+2) = f(x) for all xx. Define g:R→Rg : \mathbb{R} \to \mathbb{R} by g(x):=f ⁣(x2+1−1x)g(x) := f\!\left(\frac{\sqrt{x^2+1}-1}{x}\right) a) Find the function φ:(−1,1)→R\varphi : (-1,1) \to \mathbb{R} such that g(φ(t))=f(t)g\bigl(\varphi(t)\bigr) = f(t), that is φ−1(x)=x2+1−1x\varphi^{-1}(x) = \dfrac{\sqrt{x^2+1}-1}{x}. b) Show that ff is continuous if and only if gg is continuous and lim⁡x→∞g(x)=lim⁡x→−∞g(x)=f(1)=f(−1).\lim_{x \to \infty} g(x) = \lim_{x \to -\infty} g(x) = f(1) = f(-1).

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