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Problem ∫ d x 1 + x + x = \int \frac{dx}{\sqrt{1+x} + \sqrt{x}} = ∫ 1 + x + x d x =
A) 2 3 ( 1 + x ) 2 / 3 − 2 3 x 2 / 3 + c \frac{2}{3}(1+x)^{2/3} - \frac{2}{3}x^{2/3} + c 3 2 ( 1 + x ) 2/3 − 3 2 x 2/3 + c
B) 3 2 ( 1 + x ) 2 / 3 + 3 2 x 2 / 3 + c \frac{3}{2}(1+x)^{2/3} + \frac{3}{2}x^{2/3} + c 2 3 ( 1 + x ) 2/3 + 2 3 x 2/3 + c
C) 3 2 ( 1 + x ) 3 / 2 + 3 2 x 3 / 2 + c \frac{3}{2}(1+x)^{3/2} + \frac{3}{2}x^{3/2} + c 2 3 ( 1 + x ) 3/2 + 2 3 x 3/2 + c
D) 2 3 ( 1 + x ) 3 / 2 − 2 3 x 3 / 2 + c \frac{2}{3}(1+x)^{3/2} - \frac{2}{3}x^{3/2} + c 3 2 ( 1 + x ) 3/2 − 3 2 x 3/2 + c
A) 2 3 ( 1 + x ) 2 / 3 − 2 3 x 2 / 3 + c \frac{2}{3}(1+x)^{2/3} - \frac{2}{3}x^{2/3} + c 3 2 ( 1 + x ) 2/3 − 3 2 x 2/3 + c
B) 3 2 ( 1 + x ) 2 / 3 + 3 2 x 2 / 3 + c \frac{3}{2}(1+x)^{2/3} + \frac{3}{2}x^{2/3} + c 2 3 ( 1 + x ) 2/3 + 2 3 x 2/3 + c
C) 3 2 ( 1 + x ) 3 / 2 + 3 2 x 3 / 2 + c \frac{3}{2}(1+x)^{3/2} + \frac{3}{2}x^{3/2} + c 2 3 ( 1 + x ) 3/2 + 2 3 x 3/2 + c
D) 2 3 ( 1 + x ) 3 / 2 − 2 3 x 3 / 2 + c \frac{2}{3}(1+x)^{3/2} - \frac{2}{3}x^{3/2} + c 3 2 ( 1 + x ) 3/2 − 3 2 x 3/2 + c
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