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Mathematics
Mathematics
Problem
If
log
(
a
+
b
)
=
log
a
b
\log(a+b)=\log ab
lo
g
(
a
+
b
)
=
lo
g
ab
for
a
,
b
>
0
a,b>0
a
,
b
>
0
, then show that
(
a
3
−
1
)
(
b
3
−
1
)
−
1
b
a
(
a
+
b
)
\frac{(a^3-1)(b^3-1)-1}{ba(a+b)}
ba
(
a
+
b
)
(
a
3
−
1
)
(
b
3
−
1
)
−
1
is
3
3
3
.
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