Franz Schwabl Quantum Mechanics 4th Edit · Problem 6.3

Motion in an Electromagnetic Field

Physics — Quantum Mechanics · recursion-formula-matrix-elements

Problem

Prove the following recursion formula for the matrix elements of rkr^k ⟨rk⟩=⟨nl∣rk∣nl⟩\langle r^k \rangle = \langle nl | r^k | nl \rangle in the hydrogen atom: (k+1)n2⟨rk⟩−(2k+1)a⟨rk−1⟩+k4[(2l+1)2−k2]a2⟨rk−2⟩=0.\frac{(k+1)}{n^2} \langle r^k \rangle - (2k+1)a\langle r^{k-1} \rangle + \frac{k}{4}\left[(2l+1)^2 - k^2\right] a^2 \langle r^{k-2} \rangle = 0 \quad. Hint: It is easier to formulate the equation first for the dimensionless variable ϱ=κr\varrho = \kappa r with κ=−2mE/ℏ\kappa = \sqrt{-2mE}/\hbar and, for the computation of the ⟨ϱk⟩\langle \varrho^k \rangle, to begin with the differential equation [d2dϱ2−l(l+1)ϱ2+2nϱ−1]u(ϱ)=0.\left[\frac{d^2}{d\varrho^2} - \frac{l(l+1)}{\varrho^2} + \frac{2n}{\varrho} - 1\right] u(\varrho) = 0 \quad. Multiplying this equation by ϱk+1unl′(ϱ)\varrho^{k+1} u'_{nl}(\varrho) and ϱku\varrho^k u, respectively, and partially integrating, you can prove the claim.

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