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Problem
Problem
Suppose that
log
10
(
x
−
2
)
+
log
10
y
=
0
\log_{10}(x-2) + \log_{10} y = 0
lo
g
10
(
x
−
2
)
+
lo
g
10
y
=
0
and
x
+
y
−
2
=
(
x
+
y
)
\sqrt{x} + \sqrt{y-2} = \sqrt{(x+y)}
x
+
y
−
2
=
(
x
+
y
)
. If
x
2
t
2
−
6
+
y
6
−
2
t
2
=
6
x^{2t^2-6} + y^{6-2t^2} = 6
x
2
t
2
−
6
+
y
6
−
2
t
2
=
6
, the value of
t
1
t
2
t
3
t
4
t_1 t_2 t_3 t_4
t
1
t
2
t
3
t
4
is a. 1 b. 2 c. 4 d. 8
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