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Physics
Physics
Problem
For a particle, velocity varies with time as
v
(
t
)
=
5
sin
(
2
t
)
v(t)=5\sin(2t)
v
(
t
)
=
5
sin
(
2
t
)
, where
v
v
v
is in
m s
−
1
\text{m s}^{-1}
m s
−
1
and
t
t
t
in
s
\text{s}
s
. Determine the instantaneous acceleration at
t
=
π
4
s
t=\dfrac{\pi}{4}\,\text{s}
t
=
4
π
s
. a)
10
m s
−
2
10\,\text{m s}^{-2}
10
m s
−
2
b)
0
m s
−
2
0\,\text{m s}^{-2}
0
m s
−
2
c)
5
m s
−
2
5\,\text{m s}^{-2}
5
m s
−
2
d)
7.07
m s
−
2
7.07\,\text{m s}^{-2}
7.07
m s
−
2
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