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Problem
Problem
If
α
\alpha
α
and
β
\beta
β
are the solutions of
a
cos
θ
+
b
sin
θ
=
c
a \cos \theta + b \sin \theta = c
a
cos
θ
+
b
sin
θ
=
c
, then a.
sin
α
+
sin
β
=
2
b
c
a
2
+
b
2
\sin \alpha + \sin \beta = \frac{2bc}{a^2 + b^2}
sin
α
+
sin
β
=
a
2
+
b
2
2
b
c
b.
sin
α
sin
β
=
c
2
−
a
2
a
2
+
b
2
\sin \alpha \sin \beta = \frac{c^2 - a^2}{a^2 + b^2}
sin
α
sin
β
=
a
2
+
b
2
c
2
−
a
2
c.
sin
α
+
sin
β
=
2
a
c
b
2
+
c
2
\sin \alpha + \sin \beta = \frac{2ac}{b^2 + c^2}
sin
α
+
sin
β
=
b
2
+
c
2
2
a
c
d.
sin
α
+
sin
β
=
c
a
2
+
b
2
\sin \alpha + \sin \beta = \frac{c}{a^2 + b^2}
sin
α
+
sin
β
=
a
2
+
b
2
c
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