Mathematics

Mathematics

Problem

The locus of the mid-points of a focal chord of the ellipse x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 is a. x2a2+y2b2=exa\frac{x^2}{a^2} + \frac{y^2}{b^2} = \frac{ex}{a} b. x2a2−y2b2=exa\frac{x^2}{a^2} - \frac{y^2}{b^2} = \frac{ex}{a} c. x2+y2=a2+b2x^2 + y^2 = a^2 + b^2 d. x2−y2=a2+b2x^2 - y^2 = a^2 + b^2

Browse the problem library