Consider the fission reaction
92235U+01n→3692Kr+56141Ba+301n
with atomic masses
92235U=235.0439u,
3692Kr=91.9262u,
56141Ba=140.9144u,
01n=1.0087u.
Calculate the total energy released when 1.00g of 92235U is completely fissioned. Use NA=6.022×1023mol−1, 1u=931.5MeV/c2 and 1eV=1.6×10−19J. Choose the closest value.
a) 7.1×106MJ
b) 8.2×104MJ
c) 7.1×104MJ
d) 7.1×102MJ