Introduction to Electrodynamics · Problem 2.48

Electrostatics — David J. Griffiths

Physics · potential-hemispherical-bowl

Problem

An inverted hemispherical bowl of radius RR carries a uniform surface charge density σ\sigma. Find the potential difference between the "north pole" and the center. [Answer:(Rσ/2ϵ0)(2−1)][Answer: (R\sigma/2\epsilon_0)(\sqrt{2}-1)]

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