Physics

Physics

Problem

Which one of the following expressions represents the horizontal range RR of a projectile projected with initial speed v0v_0 at an angle θ0\theta_0 to the horizontal (acceleration due to gravity gg)? a) R=v02sin⁡2θ02gR = \dfrac{v_0^{2}\sin^{2}\theta_0}{2g} b) R=v02sin⁡θ0cos⁡θ0gR = \dfrac{v_0^{2}\sin\theta_0\cos\theta_0}{g} c) R=v02sin⁡2θ0gR = \dfrac{v_0^{2}\sin 2\theta_0}{g} d) R=v02sin⁡2θ0gR = \dfrac{v_0^{2}\sin^{2}\theta_0}{g}

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