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Mathematics
Problem
Evaluate
∫
−
1
2
(
∣
x
∣
+
1
)
d
x
\displaystyle \int_{-1}^{2} (|x|+1)\,dx
∫
−
1
2
(
∣
x
∣
+
1
)
d
x
. a)
13
2
\dfrac{13}{2}
2
13
b)
11
2
\dfrac{11}{2}
2
11
c)
5
5
5
d)
9
2
\dfrac{9}{2}
2
9
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