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Mathematics
Problem
Let
f
(
x
)
=
(
x
−
1
)
2
+
∣
x
−
1
∣
+
∣
x
+
2
∣
f(x)=(x-1)^2+|x-1|+|x+2|
f
(
x
)
=
(
x
−
1
)
2
+
∣
x
−
1∣
+
∣
x
+
2∣
. The real number at which
f
f
f
attains its minimum value is a)
x
=
2
x=2
x
=
2
b)
x
=
1
x=1
x
=
1
c)
x
=
0
x=0
x
=
0
d)
x
=
−
1
2
x=-\dfrac{1}{2}
x
=
−
2
1
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