The ionic product of water (Kw) at 40∘C is 3.00×10−7, differing from its value at 25∘C. A chemist prepares a 0.0100 M KOH solution and maintains it at 40∘C.
a. Part 1: Determine the molar concentration of hydroxide ions in the solution at 40∘C.
b. Part 2: Calculate the pOH of the solution at 40∘C.
c. Part 3: Using the provided value of Kw, calculate the pH of the solution at 40∘C.
d. Part 4: Calculate what the pH of the same 0.0100 M KOH solution would be if it were instead held at 25∘C.
e. Part 5: Explain, in terms of Kw, why pH and pOH no longer sum to 14 at 40∘C.