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Mathematics
Problem
∫
x
−
2
x
(
2
log
x
−
x
)
d
x
=
\int \frac{x-2}{x(2 \log x - x)}\,dx =
∫
x
(
2
l
o
g
x
−
x
)
x
−
2
d
x
=
(a)
log
(
2
log
x
−
x
)
+
c
\log(2 \log x - x) + c
lo
g
(
2
lo
g
x
−
x
)
+
c
(b)
log
(
1
2
log
x
−
x
)
+
c
\log\left(\frac{1}{2 \log x - x}\right) + c
lo
g
(
2
l
o
g
x
−
x
1
)
+
c
(c)
log
(
x
−
2
log
x
)
+
c
\log(x - 2 \log x) + c
lo
g
(
x
−
2
lo
g
x
)
+
c
(d)
log
(
1
x
−
2
log
x
)
+
c
\log\left(\frac{1}{x - 2 \log x}\right) + c
lo
g
(
x
−
2
l
o
g
x
1
)
+
c
(a)
log
(
2
log
x
−
x
)
+
c
\log(2 \log x - x) + c
lo
g
(
2
lo
g
x
−
x
)
+
c
(b)
log
(
1
2
log
x
−
x
)
+
c
\log\left(\frac{1}{2 \log x - x}\right) + c
lo
g
(
2
l
o
g
x
−
x
1
)
+
c
(c)
log
(
x
−
2
log
x
)
+
c
\log(x - 2 \log x) + c
lo
g
(
x
−
2
lo
g
x
)
+
c
(d)
log
(
1
x
−
2
log
x
)
+
c
\log\left(\frac{1}{x - 2 \log x}\right) + c
lo
g
(
x
−
2
l
o
g
x
1
)
+
c
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