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Mathematics
Mathematics
Problem
Let
I
=
∫
(
6
x
−
2
−
9
x
+
3
)
d
x
I=\displaystyle \int \left( \dfrac{6}{x-2}-\dfrac{9}{x+3} \right)dx
I
=
∫
(
x
−
2
6
−
x
+
3
9
)
d
x
. If
I
I
I
can be written as
ln
∣
(
x
−
2
)
p
(
x
+
3
)
q
∣
+
C
\ln|\,(x-2)^p\,(x+3)^q|+C
ln
∣
(
x
−
2
)
p
(
x
+
3
)
q
∣
+
C
, then
(
p
,
q
)
(p,q)
(
p
,
q
)
equals a)
(
6
,
9
)
(6,9)
(
6
,
9
)
b)
(
1
,
−
1
)
(1,-1)
(
1
,
−
1
)
c)
(
6
,
−
9
)
(6,-9)
(
6
,
−
9
)
d)
(
−
6
,
9
)
(-6,9)
(
−
6
,
9
)
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