Measure, Integration & Real Analysis · Problem 11C.18

Probability Measures — Sheldon Axler

Mathematics — Measure Theory · plancherel-theorem-extension

Problem

Prove that if f∈L1(R)f \in L^1(\mathbf{R}), then ∥f^∥2=∥f∥2\|\hat{f}\|_2 = \|f\|_2. [This exercise slightly improves Plancherel's Theorem (11.82) because here we have the weaker hypothesis that f∈L1(R)f \in L^1(\mathbf{R}) instead of f∈L1(R)∩L2(R)f \in L^1(\mathbf{R}) \cap L^2(\mathbf{R}). Because of Plancherel's Theorem, here you need only prove that if f∈L1(R)f \in L^1(\mathbf{R}) and ∥f∥2=∞\|f\|_2 = \infty, then ∥f^∥2=∞\|\hat{f}\|_2 = \infty.]

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