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Problem
Problem
If
k
1
=
tan
27
θ
−
tan
θ
k_1 = \tan 27\theta - \tan \theta
k
1
=
tan
27
θ
−
tan
θ
and
k
2
=
sin
θ
cos
3
θ
+
sin
3
θ
cos
9
θ
+
sin
9
θ
cos
27
θ
k_2 = \frac{\sin \theta}{\cos 3\theta} + \frac{\sin 3\theta}{\cos 9\theta} + \frac{\sin 9\theta}{\cos 27\theta}
k
2
=
c
o
s
3
θ
s
i
n
θ
+
c
o
s
9
θ
s
i
n
3
θ
+
c
o
s
27
θ
s
i
n
9
θ
then, a.
k
1
=
k
2
k_1 = k_2
k
1
=
k
2
b.
k
1
=
2
k
2
k_1 = 2k_2
k
1
=
2
k
2
c.
k
1
+
k
2
=
2
k_1 + k_2 = 2
k
1
+
k
2
=
2
d.
k
2
=
2
k
1
k_2 = 2k_1
k
2
=
2
k
1
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