Mathematics

Mathematics

Problem

∫dx9+16sin⁡2x\int \frac{dx}{9 + 16\sin^2 x} is equal to (a) 13tan⁡−1(3tan⁡x5)+C\frac{1}{3} \tan^{-1} \left( \frac{3 \tan x}{5} \right) + C (b) 13tan⁡−1(3tan⁡x5)+C\frac{1}{3} \tan^{-1} \left( \frac{3 \tan x}{5} \right) + C (c) 15tan⁡−1(tan⁡x15)+C\frac{1}{5} \tan^{-1} \left( \frac{\tan x}{15} \right) + C (d) 115tan⁡−1(5tan⁡x3)+C\frac{1}{15} \tan^{-1} \left( \frac{5 \tan x}{3} \right) + C

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